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Joseph jogs from one end A to the other ...

Joseph jogs from one end A to the other end B of a straight 300 m road in 2 minutes 50 seconds and then turns around and jogs 100 m back to point C in another 1 minute. What are Joseph's average speeds and velocities in jogging from A to C ?

Text Solution

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Distance covered by Joseph from A to B and then to C
`=300+100`
`=400`
His displacement in going from A to B and then to C = A,C = 300 - 100 = 200m
Total time taken from A to B and then to C = 2 minutes 50 second + 1 minutes
= 3 minutes 50 seconds.
= (3 `xx` 60 + 50)s
`=(180+50)s`
`=230s`
`therefore` His average speed from A to C
`=("distance")/("time")`
`=400/(230)ms^(-1)`
`=1.74ms^(-1)`
His average velocity from A to C
`=("displacement")/("time")`
`=200/230ms^(-1)`
`=0.87ms^(-1)`
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