Show that the path of a projectile is a parabola

Show that the trajectory of a projectile is a parabola, which can be expressed as y = bx - cx^2

A projectile is projected with velocity u making an angle theta with the horizontal, the equation of the path of the projectile is given by

For the maximum height of a projectile

At the highest point of the path of a projectile,

Show that the equation of the parabola with vertex (2,5) and the equation of the directrix x=1 is (y-5)^2=-4(x-2)

The velocity at the highest point of a projectile proiected 60^@ or with horizontal with velocity v is

Show that the equation of the parabola with LR=4/3 , vertex (2,1) and focus (-1/3,1) is 3y^2-6y+4x-5=0

In the diagram given below, show the path of a pollen tube from the pollen on the stigma into the embryo sac. Name the components of eggapparatus.

For a projectile motion, the horizontal range of projectile is same for any two angles which are

The equation of motion of a projectile is y =ax - bx^2 where a and b are constants of motion. The horizontal range of the projectile is