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A wire of length 20 m and area of cross ...

A wire of length 20 m and area of cross section `1.25 xx 10^(-4) m^2` is subjected to a load of 2.5 kg. (1 kgwt = 9.8N). The elongation produced in wire is `1 xx 10^(-4) ` m. Calculate Young’s modulus of the material.

Text Solution

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`Y = (FL)/(Al)`
` = (2.5 xx 9.8 xx 20)/(1.25 xx 10^(-4) xx 10^(-4))`
` = 3.92 xx 10^10 Nm^(-2)`
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