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Express T = 24.57 K in celsius and fahre...

Express T = 24.57 K in celsius and fahrenheit.

Text Solution

Verified by Experts

we have
`(T_F -32)/(180 ) = (T_c )/(100) = (T_K -273.15 )/(100)`
`therefore T_C = T_K -273 .15`
`=24.57 -273.15`
`=- 248 .58^@ C`
`(T_F -32 )/(180 ) = (T_K -273 .15 )/(100)`
` therefore T_F =(180)/(100) (T_K -273.15 ) + 32`
`= (9)/(5) (24.57 - 273.15 ) +32`
`=- 447.44 +32 `
` =- 447.44 + 32 `
` =- 415.44^@ F`
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