Home
Class 14
MATHS
Number 36005023 will be read as...

Number 36005023 will be read as

A

three crore sixty lakh five hundred twenty three

B

thirty six crore five thousand twenty three

C

three crore sixty lakh five thousand twenty three

D

three crore sixty thousand five hundred twenty three

Text Solution

Verified by Experts

The correct Answer is:
C
Promotional Banner

Similar Questions

Explore conceptually related problems

The number 81652318 will be read as eighty one crore six lakh fifty two thousand three hundred eighteen.

Number of 5 digit numbers which can be read in the same way from the left and from the right is

The following table show the total number of mails received in inbox by different users and the percentage of mails read by the users and the total number of spam received in month. Note : The spam mails didn't read by the users. The total number of mails recevied in Inbox +Total number of spam mails received. ''-'' indicates thaty you have to find the answer accroding to the question they asked. Number of mails read is what percentage of the total mails received in inbox by P. Mathur, if total number of spam mails received by P. Mathur is 38% of total mails didn't read by the user ?

In a colony of 200 members, 85 people read English newspaper, 53 people read Hindi newspaper and 120 read Telugu newspaper, 12 read newspapers of all the three languages, 21 read English and Hindi newspapers, 17 read Hindi and Telugu newspapers. Find the number of people who read almost 2 newspapers.

The arithmetic mean of 10 numbers was computed as 7.6. It was later discovered that a number 8 was wrongly read as 3 during the computation. What should be the correct mean?

The geometric mean of three numbers was conputed as 6. It was subsequently found that, in this computation, a number 8 was wrongly read as 12. What is the correct geometric mean ?

The average of 20 numbers is calcualted as 35. it is discovered later on that while calculating the avereage, one number, namely 85, was is read as 45. The correct average is :