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A piece of zinc weighing 0.635 g when tr...

A piece of zinc weighing 0.635 g when treated with excess of dilute `H_2SO_4` liberated `200 cm^3` of hydrogen at STP. Calculate the percentage purity of the zinc sample.

Text Solution

Verified by Experts

The relevant balanced chemical equation is,
`Zn + H_2SO_4 to ZnSO_4 + H_2`
It indicates that 22.4 L of hydrogen at STP = 65 g of Zn.
(where Atomic mass of Zn = 65 u)
`therefore ` 0.200 L of hydrogen at STP
`= (65g)/(22.4L) xx 0.200 L = 0.58 g`
` therefore ` percentage purity of Zn ` = (0.58)/(0.635) xx 100`
`= 91.33% `
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