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Urea [(NH2)2CO] is prepared by reacting...

Urea `[(NH_2)_2CO]` is prepared by reacting ammonia with carbon dioxide. `2NH_3(g) + CO_2(g) (NH_2)_2CO (aq) +H_2O(l)` In one process, 637.2 g of NH3 are treated with 1142 g of `CO_2` .
Which of the two reactants is the limiting reagent ?

Text Solution

Verified by Experts

We carry out two separate calculations. First : If 637.2 g of `NH_3` reacts completely, calculate the number of moles of `(NH_2)_2CO` , that could be produced, by the following relation.
mass of `NH_3 to ` mass of `NH_3 to` mass of `(NH_4)_2CO`
moles of `(NH_2)_2CO = 637.2 g NH_3 xx (1"mol" NH_3)/(17.03g NH_3) xx (1"mol" (NH_4)_2CO)/(2"mol"NH_3)`
` = 18.71 "moles" (NH_2)_2CO`
It follows, therefore, that NH3 must be the limiting reagent because it produces `(alpha)` smaller amount of `(NH_2)_2CO`
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