The volume occupied by a given mass of a gas at 298 K is 25 mL at 1 atmosphere pressure. Calculate the volume of the gas if pressure is increased to 1.25 atmosphere at constant temperature.
Given : `P_1` = 1 atm, `V_1` = 25 mL
`P_2`= 1.25 atm, `V_2` = ?

Explanation

According to Boyle’s law,
`P_1 V_1 = P_2V_2`
ubstituting the values of `P_1V_1` and `P_2` in the above expression we get
`V_2 = (P_1V_1)/(P_2) = (1xx25)/(1.25) = 20 ml`
Volume occupied by the gas is 20 mL