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If vec(a) = hat(i) + hat(j) + hat(k), ve...

If `vec(a) = hat(i) + hat(j) + hat(k), vec(a).vec(b) = 1` and `vec(a) xx vec(b) = hat(j) - hat(k)` then prove that `bar(b) = hat(i)`.

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The correct Answer is:
`hat(i) = bar(b)`
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