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int(1)/(2cos x+sin2x)*dx...

`int(1)/(2cos x+sin2x)*dx`

Text Solution

Verified by Experts

The correct Answer is:
`1/8[log((1+sinx)/(1-sinx))-(2)/(1+sinx)]+c`
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Knowledge Check

  • int(1)/(cosx-cos^(2)x)*dx=

    A
    `log("cosec "x-cotx)+tan(x/2)+c`
    B
    `sin2x-cosx+c`
    C
    `log(secx+tanx)-cot(x/2)+c`
    D
    `cos 2x-sinx+c`
  • int(cos2x-1)/(cos2x+1)*dx=

    A
    `tanx-x+c`
    B
    `x+tanx+c`
    C
    `x-tanx+c`
    D
    `-x-cot x+c`
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