When 1 mole of benzene is mixed with 1 mole of toluene The vapour will contain: (Given : vapour of benzene = 12.8kPa and vapour pressure of toluene = 3.85 kPa).

Options

A. equal amount of benzene and toluene as it forms an ideal solution
B. unequal amount of benzene and toluene as it forms a non ideal solution
C. higher percentage of benzene
D. higher percentage of toluene

Answer

C

Explanation

When l mole of benzene is mixed with 1 mole of toluene trieivapont, Will contain higher percentage of benzene As it is an ideal solution follows Raoulis laws The vapour pressure of the solution depends on the mole fraction of the solvent ,
`P_("soln")=X_("solvent")P_(solvent)^0`
`P_("soln")` is the vapour pressure of the solution is the mole fraction of the solvent `P_("soln")`is the vapour pressure of the pure solvent Since the mole fraction of both the components is same, but the vapour pressure of benzene is higher than the toluene, cils percentage will be greater in the vapour of the solution.