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Assertion (A): 0.1 M solution of KCl has...

Assertion (A): 0.1 M solution of KCl has great osmotic pressure than 0.1 M solution of glucose at same temperature.
Reason (R): In solution KCl dissociates to produce more number of particles.

A

Both A and R are true and R is the correct explanation of A

B

Both A and R are true but R is NOT the correct explanation of A

C

A is true but R is false

D

A is false and R is True

Text Solution

AI Generated Solution

The correct Answer is:
To solve the question, we need to analyze the assertion and reason provided regarding the osmotic pressure of KCl and glucose solutions. ### Step-by-Step Solution: 1. **Understanding Osmotic Pressure**: Osmotic pressure (π) is given by the formula: \[ \pi = iCRT \] where: - \(i\) = van 't Hoff factor (number of particles the solute dissociates into), - \(C\) = molarity of the solution, - \(R\) = ideal gas constant, - \(T\) = temperature in Kelvin. 2. **Analyzing KCl Solution**: - KCl is an ionic compound that dissociates in solution: \[ \text{KCl} \rightarrow \text{K}^+ + \text{Cl}^- \] - For KCl, the van 't Hoff factor \(i = 2\) (since it produces 2 particles: K⁺ and Cl⁻). - Therefore, the osmotic pressure for 0.1 M KCl is: \[ \pi_{\text{KCl}} = iCRT = 2 \times 0.1 \times RT = 0.2RT \] 3. **Analyzing Glucose Solution**: - Glucose is a non-electrolyte and does not dissociate in solution: \[ \text{C}_6\text{H}_{12}\text{O}_6 \rightarrow \text{C}_6\text{H}_{12}\text{O}_6 \] - For glucose, the van 't Hoff factor \(i = 1\). - Therefore, the osmotic pressure for 0.1 M glucose is: \[ \pi_{\text{glucose}} = iCRT = 1 \times 0.1 \times RT = 0.1RT \] 4. **Comparing Osmotic Pressures**: - From the calculations: \[ \pi_{\text{KCl}} = 0.2RT \quad \text{and} \quad \pi_{\text{glucose}} = 0.1RT \] - Clearly, \(0.2RT > 0.1RT\), which means the osmotic pressure of the KCl solution is greater than that of the glucose solution. 5. **Conclusion**: - The assertion (A) that "0.1 M solution of KCl has greater osmotic pressure than 0.1 M solution of glucose at the same temperature" is **true**. - The reason (R) that "in solution KCl dissociates to produce more number of particles" is also **true** and correctly explains the assertion. ### Final Answer: Both the assertion and reason are true, and the reason correctly explains the assertion.

To solve the question, we need to analyze the assertion and reason provided regarding the osmotic pressure of KCl and glucose solutions. ### Step-by-Step Solution: 1. **Understanding Osmotic Pressure**: Osmotic pressure (π) is given by the formula: \[ \pi = iCRT ...
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