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A brown ring is formed in the ring test ...

A brown ring is formed in the ring test for `NO_(3)^(-)` ion. It is due to the formation of

A

`[Fe(H_2O)_(5)(NO)]^(2+)`

B

`FeSO_(4)NO_(2)`

C

`[Fe(H_(2)O)_(4).(NO_(2)]^(2+)`

D

`FeSO_(4).HNO_(3)`

Text Solution

Verified by Experts

The correct Answer is:
A
When freshly prepared solution of ferrous sulphate `(FeSO_(4))` is added in a solution contatining `NO_(3)^(-)` ion, formation of a brown coloured complex will take place. This is called as brown ring test of nitrate. Hence, two moles of ammonia will produce two moles of NO.
`NO_3^(-)+3Fe^(2+)+4H^(+)rarrNO+3Fe^(3+)+2H_(2)O`
`[Fe(H_2O)_(6)]^(2+)+NOrarrunderset("Brown ring ")([Fe(H_2O)_(5)(NO)O]^(2+))+H_(2)O`
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