When `XeF_(4)` is partially hydrolysed, it yields

Options

A. `XeSO_(3)`
B. `XeOF_(2)`
C. `XeOF_(4)`
D. `XeF_(2)`

Explanation

To solve the question regarding the partial hydrolysis of \( XeF_4 \), we will follow these steps:

### Step 1: Understand Hydrolysis
Hydrolysis refers to the chemical reaction of a substance with water. In this case, we are looking at the reaction of xenon tetrafluoride (\( XeF_4 \)) with water.

### Step 2: Write the Reaction for Partial Hydrolysis
When \( XeF_4 \) is partially hydrolyzed, it reacts with water. The general reaction can be represented as:
\[ XeF_4 + H_2O \rightarrow XeF_2 + HF \]
In this reaction, \( XeF_4 \) reacts with one molecule of water to produce \( XeF_2 \) and hydrofluoric acid (HF).

### Step 3: Identify the Products
From the reaction, we can see that the products of the partial hydrolysis of \( XeF_4 \) are:
- Xenon difluoride (\( XeF_2 \))
- Hydrofluoric acid (HF)

### Step 4: Conclusion
Thus, the products formed when \( XeF_4 \) is partially hydrolyzed are \( XeF_2 \) and \( HF \).

### Final Answer
When \( XeF_4 \) is partially hydrolyzed, it yields \( XeF_2 \) and \( HF \).

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