How many ions are produced from the complex `[Co(NH_(3))_(5)Cl]Cl_(2)` in solution ?

Options

A. 4
B. 2
C. 3
D. 5

Explanation

To determine how many ions are produced from the complex \([Co(NH_3)_5Cl]Cl_2\) in solution, we can follow these steps:

### Step 1: Identify the Coordination Complex
The given complex is \([Co(NH_3)_5Cl]Cl_2\). Here, cobalt (Co) is the central metal ion, surrounded by five ammonia (NH₃) ligands and one chloride (Cl) ligand.

### Step 2: Understand the Structure
In the coordination complex, the ligands (NH₃ and Cl) are bonded to the cobalt ion and form a coordination sphere. The chloride ions outside the coordination sphere are considered counter ions.

### Step 3: Determine the Counter Ions
The formula indicates that there are two chloride ions outside the coordination sphere, which are represented by \(Cl_2\).

### Step 4: Analyze Ionization in Solution
When the complex is dissolved in solution:
- The coordination complex \([Co(NH_3)_5Cl]^2+\) remains intact as one complex ion.
- The two chloride ions \(Cl^-\) dissociate into the solution.

### Step 5: Count the Total Ions
- From the complex ion \([Co(NH_3)_5Cl]^2+\), we have **1 complex ion**.
- From the two chloride ions, we have **2 chloride ions**.

Adding these together gives us:
\[ 1 \text{ (complex ion)} + 2 \text{ (chloride ions)} = 3 \text{ ions in total} \]

### Final Answer
The total number of ions produced from the complex \([Co(NH_3)_5Cl]Cl_2\) in solution is **3**.

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