The pair `[Co(NH_(3))_(4)Cl_(2)]Br_(2)` and `[Co(NH_(3))_(4)Br_(2)]Cl_(2)` will show

Options

A. Linkage isomerism
B. Hydrate isomerism
C. Ionization isomerism
D. Coordinate isomerism

Explanation

To solve the question regarding the coordination compounds `[Co(NH3)4Cl2]Br2` and `[Co(NH3)4Br2]Cl2`, we need to analyze the structural differences between these two complexes and determine what type of isomerism they exhibit.

### Step-by-Step Solution:

1. **Identify the Coordination Compounds**:
- The first compound is `[Co(NH3)4Cl2]Br2`.
- The second compound is `[Co(NH3)4Br2]Cl2`.

2. **Count the Ligands and Ions**:
- In both complexes, we have:
- 1 Cobalt (Co) ion.
- 4 Ammonia (NH3) ligands.
- 2 Chloride (Cl) ligands in the first complex and 2 Bromide (Br) ligands in the second complex.
- Additionally, each complex has 2 counter ions (Br or Cl).

3. **Analyze the Composition**:
- The first complex `[Co(NH3)4Cl2]Br2` has:
- 4 NH3, 2 Cl as ligands, and 2 Br as counter ions.
- The second complex `[Co(NH3)4Br2]Cl2` has:
- 4 NH3, 2 Br as ligands, and 2 Cl as counter ions.

4. **Determine the Type of Isomerism**:
- The two complexes have the same molecular formula but differ in the arrangement of the ligands and counter ions.
- The difference lies in which ions are associated with the cobalt complex and which are free in the solution.
- This type of isomerism, where the same coordination compound can have different arrangements of ligands and counter ions, is known as **ionization isomerism**.

5. **Conclusion**:
- Therefore, the pair `[Co(NH3)4Cl2]Br2` and `[Co(NH3)4Br2]Cl2` will show **ionization isomerism**.

### Final Answer:
The pair `[Co(NH3)4Cl2]Br2` and `[Co(NH3)4Br2]Cl2` will show **ionization isomers**.

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