Read the passage given below and answer the following questions:
Alkyl/Aryl halides may be classified as mono, di or polyhalogen compounds depending on one, two or more halogen atoms in their structures. Alkyl halides are prepared by free radical halogenation of alkanes, addition of halogen acids to alkenes and replacement of -OH group of alcohols with halogens using phosphorus halides, thionyl chloride or halogen acids. Aryl halides are prepared by electrophilic substitution to arenes.
The following questions are multiple choice questions.
Choose the most appropriate answer:
Complete the reaction:
`H_(3)C- Br + AgF to`

Options

A. `H_(3)C-Br + AgF to H_(3)C -F + AgBr`
B. `H_(3)C-Br + AgF to Br-CH_(2)F + AgH`
C. `H_(3)C -Br + AgF to [Ag(CH_(3))]F + Br`
D. None of the above

Explanation

To complete the reaction of methyl bromide (CH₃Br) with silver fluoride (AgF), we will follow these steps:

### Step 1: Identify the Reactants
We have two reactants:
- Methyl bromide (CH₃Br), which is an alkyl halide.
- Silver fluoride (AgF), which is a transition metal fluoride.

### Step 2: Understand the Reaction Type
This reaction is known as the Swartz reaction, where an alkyl halide reacts with a transition metal fluoride. In this case, the bromine atom in methyl bromide will be replaced by a fluorine atom from silver fluoride.

### Step 3: Write the Reaction
The general form of the reaction can be expressed as:
\[ R-X + AgF \rightarrow R-F + AgX \]
Where:
- \( R \) is the alkyl group (in this case, CH₃).
- \( X \) is the halogen (in this case, Br).

Substituting the specific reactants:
\[ CH₃Br + AgF \rightarrow CH₃F + AgBr \]

### Step 4: Identify the Products
From the reaction, we can see that:
- The product formed is methyl fluoride (CH₃F).
- The byproduct is silver bromide (AgBr).

### Final Reaction
Thus, the complete reaction is:
\[ CH₃Br + AgF \rightarrow CH₃F + AgBr \]

### Conclusion
The correct answer to the question is that the reaction of methyl bromide with silver fluoride produces methyl fluoride and silver bromide.

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