Predict the product of the following reaction.
` CH_3-underset(CH_3) underset(|) C= O underset((ii) KOH//Glycol. Delta ) overset((i) N_2N-NH_2)to ? `

Options

A. ` CH_3 CH_2CH_3`
B. ` CH_3CHOHCH_3`
C. ` CH_3CH_2CHO`
D. ` CH_3CONHCH_3`

Explanation

To predict the product of the given reaction, we will follow the steps outlined in the video transcript. The reaction involves a carbonyl compound (an aldehyde or ketone) and two subsequent reactions: one with hydrazine (NH2-NH2) and another with KOH in glycol under heat.

### Step-by-Step Solution:

1. **Identify the Starting Compound:**
The starting compound is CH3C(=O)CH3, which is acetone (a ketone).

2. **Reaction with Hydrazine (NH2-NH2):**
When acetone reacts with hydrazine, it forms a hydrazone. The reaction is as follows:
\[ \text{CH}_3\text{C(=O)CH}_3 + \text{NH}_2\text{NH}_2 \rightarrow \text{CH}_3\text{C(=N-NH}_2)\text{CH}_3 + \text{H}_2\text{O} \]
This step involves the nucleophilic attack of hydrazine on the carbonyl carbon, followed by the elimination of water.

3. **Wolff-Kishner Reduction:**
The formed hydrazone then undergoes Wolff-Kishner reduction when treated with KOH in glycol and heated. This reduction converts the hydrazone to an alkane:
\[ \text{CH}_3\text{C(=N-NH}_2)\text{CH}_3 + \text{KOH (heat)} \rightarrow \text{CH}_3\text{CH}_2\text{CH}_3 + \text{N}_2 + \text{H}_2\text{O} \]
Here, the carbonyl group is reduced to a methylene group (–CH2–), resulting in the formation of propane (C3H8).

4. **Final Product:**
The final product of the reaction is propane (C3H8), which can be represented as:
\[ \text{CH}_3\text{CH}_2\text{CH}_3 \]

### Final Answer:
The product of the reaction is **propane (C3H8)**.