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int e^(x) sec x (1 + tan x) dx is equal ...

`int e^(x) sec x (1 + tan x) dx` is equal to

A

`e^(x) cos x + C`

B

`e^(x) sec x + C`

C

`e^(x) sin x + C`

D

`e^(x) tan x + C`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the integral \( \int e^x \sec x (1 + \tan x) \, dx \), we can use a substitution method based on the derivative of a function. Let's break it down step by step. ### Step 1: Rewrite the Integral We start with the integral: \[ \int e^x \sec x (1 + \tan x) \, dx \] We can rewrite \( (1 + \tan x) \) as \( \sec x + \sec x \tan x \): \[ \int e^x \sec x (1 + \tan x) \, dx = \int e^x \sec x \, dx + \int e^x \sec x \tan x \, dx \] ### Step 2: Identify the Function Notice that the derivative of \( \sec x \) is \( \sec x \tan x \). This suggests that we can use integration by parts or a specific formula for integrals involving \( e^x \) and the derivative of a function. ### Step 3: Apply the Integration Formula We can use the formula: \[ \int e^x f(x) \, dx = e^x f(x) - \int e^x f'(x) \, dx \] where \( f(x) = \sec x \) and \( f'(x) = \sec x \tan x \). ### Step 4: Substitute into the Formula Applying the formula: \[ \int e^x \sec x \, dx = e^x \sec x - \int e^x \sec x \tan x \, dx \] Now, we can substitute this back into our original integral: \[ \int e^x \sec x (1 + \tan x) \, dx = \int e^x \sec x \, dx + \int e^x \sec x \tan x \, dx \] This simplifies to: \[ = \left( e^x \sec x - \int e^x \sec x \tan x \, dx \right) + \int e^x \sec x \tan x \, dx \] ### Step 5: Simplify the Expression Notice that the \( \int e^x \sec x \tan x \, dx \) terms cancel out: \[ = e^x \sec x + C \] where \( C \) is the constant of integration. ### Final Answer Thus, the integral evaluates to: \[ \int e^x \sec x (1 + \tan x) \, dx = e^x \sec x + C \]
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