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Assertion (A) : int e^(x)[sin x - cos x]...

Assertion (A) : `int e^(x)[sin x - cos x] dx = e^(x) sin x + C`
Reason (R) : `int e^(x)[f(x) + f'(x)] dx = e^(x)f(x) + c`

A

Both A and R are true and R is the correct explanation of A.

B

Both A and R are true and R is NOT the correct explanation of A.

C

A is true but R is false

D

A is false and R is true

Text Solution

AI Generated Solution

The correct Answer is:
To solve the given assertion and reason, we will analyze both statements step by step. ### Step 1: Understand the Assertion The assertion states that: \[ \int e^x [\sin x - \cos x] \, dx = e^x \sin x + C \] ### Step 2: Analyze the Integral We can rewrite the integral: \[ \int e^x [\sin x - \cos x] \, dx = \int e^x \sin x \, dx - \int e^x \cos x \, dx \] ### Step 3: Apply Integration by Parts We will use integration by parts for both integrals. Recall the formula: \[ \int u \, dv = uv - \int v \, du \] Let’s first compute \(\int e^x \sin x \, dx\): - Let \(u = \sin x\) and \(dv = e^x \, dx\) - Then, \(du = \cos x \, dx\) and \(v = e^x\) Applying integration by parts: \[ \int e^x \sin x \, dx = e^x \sin x - \int e^x \cos x \, dx \] Now we need to compute \(\int e^x \cos x \, dx\): - Let \(u = \cos x\) and \(dv = e^x \, dx\) - Then, \(du = -\sin x \, dx\) and \(v = e^x\) Applying integration by parts again: \[ \int e^x \cos x \, dx = e^x \cos x + \int e^x \sin x \, dx \] ### Step 4: Set Up the Equation Now we have two equations: 1. \(\int e^x \sin x \, dx = e^x \sin x - \int e^x \cos x \, dx\) 2. \(\int e^x \cos x \, dx = e^x \cos x + \int e^x \sin x \, dx\) Let \(I_1 = \int e^x \sin x \, dx\) and \(I_2 = \int e^x \cos x \, dx\). We can express \(I_1\) and \(I_2\) in terms of each other: \[ I_1 = e^x \sin x - I_2 \] \[ I_2 = e^x \cos x + I_1 \] ### Step 5: Substitute and Solve Substituting \(I_2\) into the equation for \(I_1\): \[ I_1 = e^x \sin x - (e^x \cos x + I_1) \] \[ I_1 + I_1 = e^x \sin x - e^x \cos x \] \[ 2I_1 = e^x (\sin x - \cos x) \] \[ I_1 = \frac{1}{2} e^x (\sin x - \cos x) \] ### Step 6: Conclusion Thus, we find: \[ \int e^x [\sin x - \cos x] \, dx = \frac{1}{2} e^x (\sin x - \cos x) + C \] This shows that the assertion is incorrect because it states the integral equals \(e^x \sin x + C\). ### Step 7: Analyze the Reason The reason states: \[ \int e^x [f(x) + f'(x)] \, dx = e^x f(x) + C \] This is a correct statement, as it follows from the product rule of differentiation. ### Final Conclusion - The assertion (A) is **false**. - The reason (R) is **true**.
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