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int(0)^(pi)e^(x)(tan x + sec^(2)x) dx = ...

`int_(0)^(pi)e^(x)(tan x + sec^(2)x) dx` = ______.

A

0

B

1

C

`-1`

D

`-e^(pi)`

Text Solution

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The correct Answer is:
To solve the integral \( \int_{0}^{\pi} e^{x} (\tan x + \sec^{2} x) \, dx \), we will use the integration technique based on the formula for integrating the product of an exponential function and the sum of a function and its derivative. ### Step-by-step Solution: 1. **Identify the Components**: We have \( e^{x} \) multiplied by \( \tan x + \sec^{2} x \). Notice that \( \sec^{2} x \) is the derivative of \( \tan x \). Thus, we can let: - \( f(x) = \tan x \) - \( f'(x) = \sec^{2} x \) 2. **Recognize the Integral Form**: The integral can be recognized as fitting the form: \[ \int e^{x} (f(x) + f'(x)) \, dx \] which integrates to: \[ e^{x} f(x) + C \] 3. **Apply the Formula**: Therefore, we can write: \[ \int e^{x} (\tan x + \sec^{2} x) \, dx = e^{x} \tan x + C \] 4. **Evaluate the Definite Integral**: Now we need to evaluate this from \( 0 \) to \( \pi \): \[ \left[ e^{x} \tan x \right]_{0}^{\pi} \] 5. **Calculate the Upper Limit**: - At \( x = \pi \): \[ e^{\pi} \tan(\pi) = e^{\pi} \cdot 0 = 0 \] 6. **Calculate the Lower Limit**: - At \( x = 0 \): \[ e^{0} \tan(0) = 1 \cdot 0 = 0 \] 7. **Combine the Results**: Now substituting the limits into the evaluated integral: \[ 0 - 0 = 0 \] ### Final Answer: Thus, the value of the integral \( \int_{0}^{\pi} e^{x} (\tan x + \sec^{2} x) \, dx \) is \( \boxed{0} \).
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