Home
Class 12
PHYSICS
A Young's double slit experiment is perf...

A Young's double slit experiment is performed with blue (wavelength 460 nm) and green light (wavelength 550 nm) respectively. If y is the distance of 4th maximum from the central fringe then

A

`y_B=y_G`

B

`y_Bgty_G`

C

`y_Ggty_B`

D

`y_B//y_G= 550//460`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem of finding the distance of the 4th maximum (Y4) from the central fringe in a Young's double slit experiment using blue and green light, we can follow these steps: ### Step-by-Step Solution: 1. **Understand the Formula for Fringe Position**: The position of the nth maximum (Yn) in a Young's double slit experiment is given by the formula: \[ Y_n = \frac{n \lambda D}{d} \] where: - \( Y_n \) = distance of the nth maximum from the central fringe, - \( n \) = order of the maximum (in this case, \( n = 4 \)), - \( \lambda \) = wavelength of light, - \( D \) = distance from the slits to the screen, - \( d \) = distance between the slits. 2. **Calculate Y4 for Blue Light**: For blue light with a wavelength \( \lambda_{blue} = 460 \, \text{nm} = 460 \times 10^{-9} \, \text{m} \): \[ Y_4^{blue} = \frac{4 \cdot \lambda_{blue} \cdot D}{d} = \frac{4 \cdot 460 \times 10^{-9} \cdot D}{d} \] 3. **Calculate Y4 for Green Light**: For green light with a wavelength \( \lambda_{green} = 550 \, \text{nm} = 550 \times 10^{-9} \, \text{m} \): \[ Y_4^{green} = \frac{4 \cdot \lambda_{green} \cdot D}{d} = \frac{4 \cdot 550 \times 10^{-9} \cdot D}{d} \] 4. **Compare the Distances**: Since both expressions have the same factors \( \frac{4D}{d} \), we can compare the wavelengths: - \( Y_4^{blue} \) is proportional to \( 460 \times 10^{-9} \) - \( Y_4^{green} \) is proportional to \( 550 \times 10^{-9} \) Since \( 550 \, \text{nm} > 460 \, \text{nm} \), it follows that: \[ Y_4^{green} > Y_4^{blue} \] 5. **Conclusion**: Therefore, the distance of the 4th maximum from the central fringe is greater for green light than for blue light. ### Final Answer: The distance of the 4th maximum from the central fringe is greater for green light (550 nm) than for blue light (460 nm). ---

To solve the problem of finding the distance of the 4th maximum (Y4) from the central fringe in a Young's double slit experiment using blue and green light, we can follow these steps: ### Step-by-Step Solution: 1. **Understand the Formula for Fringe Position**: The position of the nth maximum (Yn) in a Young's double slit experiment is given by the formula: \[ Y_n = \frac{n \lambda D}{d} ...
Promotional Banner