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Without actually performing the long division, state whether the rational number will have a terminating decimal expansion or a non - terminating repeating decimal expansion
`(64)/(455)`

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To determine whether the rational number \( \frac{64}{455} \) has a terminating decimal expansion or a non-terminating repeating decimal expansion, we can follow these steps: ### Step 1: Identify the denominator The denominator of the given rational number is \( 455 \). ### Step 2: Prime factorization of the denominator We need to perform the prime factorization of \( 455 \): - Start by dividing \( 455 \) by the smallest prime number, which is \( 5 \): \[ 455 \div 5 = 91 \] - Next, factor \( 91 \): - \( 91 \) can be divided by \( 7 \): \[ 91 \div 7 = 13 \] - Thus, the complete prime factorization of \( 455 \) is: \[ 455 = 5 \times 7 \times 13 \] ### Step 3: Analyze the prime factors For a rational number \( \frac{p}{q} \) to have a terminating decimal expansion, the prime factorization of \( q \) must consist only of the prime factors \( 2 \) and/or \( 5 \). ### Step 4: Check the prime factors of the denominator From the prime factorization: \[ 455 = 5 \times 7 \times 13 \] We can see that besides \( 5 \), there are additional prime factors \( 7 \) and \( 13 \). ### Step 5: Conclusion Since the denominator \( 455 \) contains prime factors other than \( 2 \) and \( 5 \) (specifically \( 7 \) and \( 13 \)), the rational number \( \frac{64}{455} \) will have a non-terminating repeating decimal expansion. ### Final Answer: The rational number \( \frac{64}{455} \) has a non-terminating repeating decimal expansion. ---
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OSWAL PUBLICATION-REAL NUMBERS-NCERT Corner (Exercise - 1.4)
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