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Two different dice one thrown together. ...

Two different dice one thrown together. Find the probability that the numbers obtained :
have a sum less than 7

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To solve the problem of finding the probability that the sum of the numbers obtained from throwing two different dice is less than 7, we can follow these steps: ### Step-by-Step Solution: 1. **Determine the Total Outcomes**: When two dice are thrown, each die has 6 faces. Therefore, the total number of outcomes when throwing two dice is: \[ \text{Total Outcomes} = 6 \times 6 = 36 \] 2. **Identify Favorable Outcomes**: We need to find the pairs of numbers (from the two dice) that sum to less than 7. Let's list them: - For the first die showing 1: - (1, 1) → Sum = 2 - (1, 2) → Sum = 3 - (1, 3) → Sum = 4 - (1, 4) → Sum = 5 - (1, 5) → Sum = 6 - For the first die showing 2: - (2, 1) → Sum = 3 - (2, 2) → Sum = 4 - (2, 3) → Sum = 5 - (2, 4) → Sum = 6 - For the first die showing 3: - (3, 1) → Sum = 4 - (3, 2) → Sum = 5 - (3, 3) → Sum = 6 - For the first die showing 4: - (4, 1) → Sum = 5 - (4, 2) → Sum = 6 - For the first die showing 5: - (5, 1) → Sum = 6 The pairs that yield sums less than 7 are: - (1, 1), (1, 2), (1, 3), (1, 4), (1, 5) - (2, 1), (2, 2), (2, 3), (2, 4) - (3, 1), (3, 2) - (4, 1) - (5, 1) Counting these pairs, we have: - 5 outcomes from the first die showing 1 - 4 outcomes from the first die showing 2 - 3 outcomes from the first die showing 3 - 2 outcomes from the first die showing 4 - 1 outcome from the first die showing 5 Adding these gives: \[ 5 + 4 + 3 + 2 + 1 = 15 \text{ favorable outcomes} \] 3. **Calculate the Probability**: The probability \( P \) of getting a sum less than 7 is given by the formula: \[ P(\text{Sum} < 7) = \frac{\text{Number of Favorable Outcomes}}{\text{Total Outcomes}} = \frac{15}{36} \] 4. **Simplify the Probability**: We can simplify \( \frac{15}{36} \) by dividing both the numerator and the denominator by their greatest common divisor (GCD), which is 3: \[ P(\text{Sum} < 7) = \frac{15 \div 3}{36 \div 3} = \frac{5}{12} \] ### Final Answer: The probability that the sum of the numbers obtained from throwing two dice is less than 7 is: \[ \frac{5}{12} \]
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