Two different dice one thrown together. Find the probability that the numbers obtained :
is a doublet of odd numbers

Answer

To solve the problem of finding the probability that the numbers obtained from throwing two different dice is a doublet of odd numbers, we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Total Outcomes:**
When two dice are thrown, each die has 6 faces. Therefore, the total number of outcomes when throwing two dice is calculated as:
\[ \text{Total Outcomes} = 6 \times 6 = 36 \]

2. **Identify the Favorable Outcomes:**
A doublet of odd numbers means that both dice show the same odd number. The odd numbers on a die are 1, 3, and 5. Thus, the possible doublets of odd numbers are:
- (1, 1)
- (3, 3)
- (5, 5)

Hence, the total number of favorable outcomes is:
\[ \text{Favorable Outcomes} = 3 \quad \text{(i.e., (1,1), (3,3), (5,5))} \]

3. **Calculate the Probability:**
The probability of an event is given by the formula:
\[ \text{Probability} = \frac{\text{Favorable Outcomes}}{\text{Total Outcomes}} \]
Substituting the values we found:
\[ \text{Probability} = \frac{3}{36} = \frac{1}{12} \]

### Final Answer:
The probability that the numbers obtained is a doublet of odd numbers is:
\[ \frac{1}{12} \]