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In a class 20% of students are below 14 ...

In a class `20%` of students are below 14 years of age . Out of the remaining students `10%` are of the age 14 - 15years and ratio of students who are between 15 - 16 years of age to student above 16 years of age is 3 : 2 . If the number of students who are above 16 years is 72 , what is the total number of students in the class ?

A

200

B

250

C

300

D

400

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem step by step, we will follow the information provided in the question carefully. ### Step 1: Define the total number of students Let the total number of students in the class be \( n \). ### Step 2: Calculate the number of students below 14 years of age According to the question, 20% of the students are below 14 years of age. Therefore, the number of students below 14 years is: \[ \text{Number of students below 14} = 0.2n \] ### Step 3: Calculate the remaining students The remaining students after excluding those below 14 years of age will be: \[ \text{Remaining students} = n - 0.2n = 0.8n \] ### Step 4: Calculate the number of students aged 14 to 15 years Out of the remaining students, 10% are aged between 14 to 15 years. Thus, the number of students aged 14 to 15 years is: \[ \text{Number of students aged 14 to 15} = 0.1 \times 0.8n = 0.08n \] ### Step 5: Calculate the number of students aged 15 to 16 years and above 16 years Let \( x \) be the number of students aged between 15 to 16 years. The ratio of students aged 15 to 16 years to those above 16 years is given as 3:2. We also know that the number of students above 16 years is 72. Therefore, we can set up the following relationship: \[ \frac{x}{72} = \frac{3}{2} \] ### Step 6: Solve for \( x \) Cross-multiplying gives: \[ 2x = 3 \times 72 \] \[ 2x = 216 \] \[ x = \frac{216}{2} = 108 \] ### Step 7: Calculate the total number of students Now we can sum up all the students: - Students below 14 years: \( 0.2n \) - Students aged 14 to 15 years: \( 0.08n \) - Students aged 15 to 16 years: \( 108 \) - Students above 16 years: \( 72 \) Setting up the equation: \[ n = 0.2n + 0.08n + 108 + 72 \] \[ n = 0.28n + 180 \] ### Step 8: Solve for \( n \) Rearranging gives: \[ n - 0.28n = 180 \] \[ 0.72n = 180 \] \[ n = \frac{180}{0.72} = 250 \] ### Conclusion The total number of students in the class is \( \boxed{250} \).
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