In a code language if 'APPEAL' is coded as '256572' and 'PLAY' is coded as '7259' then in the same language 'PEARL' will be coded as (each number code stands for unique alphabet ) ______

Options

A. 2 5 7 6 8
B. 2 5 3 8 7
C. 6 7 5 2 2
D. 2 5 6 7 9

Answer

To solve the problem of coding the word 'PEARL' based on the given codes for 'APPEAL' and 'PLAY', we can follow these steps:

### Step 1: Identify the Codes for Each Letter
From the coding provided:
- 'APPEAL' is coded as '256572'
- 'PLAY' is coded as '7259'

We will first decode the letters from 'APPEAL':
- A = 2 (first letter)
- P = 5 (second letter, appears twice)
- E = 6 (third letter)
- L = 7 (fourth letter)

Now, let's decode 'PLAY':
- P = 5 (first letter)
- L = 7 (second letter)
- A = 2 (third letter)
- Y = 9 (fourth letter)

### Step 2: Compile the Codes
From the above, we can summarize the codes for the letters:
- A = 2
- P = 5
- E = 6
- L = 7
- Y = 9

Now, we need to find the code for 'PEARL':
- P = 5
- E = 6
- A = 2
- R = ? (we do not have the code for R yet)
- L = 7

### Step 3: Determine the Code for R
Since we don't have the code for R, we can check the options provided. We know that:
- The codes we have so far are 5 (P), 6 (E), 2 (A), and 7 (L).
- The only letter left is R, which we need to find a unique code for.

### Step 4: Analyze the Options
We will analyze the options to find a unique digit for R that does not conflict with the existing codes:
1. If we check the options, we see that:
- Option 1: 25768
- Option 2: 25769
- Option 3: 25767
- Option 4: 25789

From the options, we see that:
- Option 1 has the digits 2, 5, 7, 6, and 8. Here, 8 is a unique code for R.
- Option 2 has 9, which is already assigned to Y.
- Option 3 has 7 repeated, which is not valid.
- Option 4 has 9, which is already assigned to Y.

### Step 5: Conclusion
The only option that fits all the criteria is Option 1: 25768, where R is coded as 8.

Thus, the code for 'PEARL' is **25768**.