The focus of the parabola...

The focus of the parabola

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The mirror image of the focus to the parabola 4(x + y) = y^(2) w.r.t. the directrix is

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Coordinates of focus of the parabola x^(2)-2ax+2ay=0 will be

The focus of a parabola is (1,2) and the point of intersection of the directrix and axis is (2,3).Then the equation of the parabola is

Write the distance between the vertex and focus of the parabola y^(2)+6y+2x+5=0

The vertex and focus of the, parabola 2y^(2)+5x-6y+1=0 are respectively.

Find the point on the parabola y^(2)=4ax(a>0) which forms a triangle of area 3a^(2) with the vertex and focus of the parabola.

In the adjacent figure a parabola is drawn to pass through the vertices B,C and D of the square ABCD. If A(2,1),C(2,3) , then focus of this parabola is

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If the focus of a parabola is at (0,-3) and its directrix is y = 3, then its equation is

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