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If two positive intergers a and b are wr...

If two positive intergers a and b are written as `a=x^(3)y^(2)` and `b=xy^(3),x,y` are prime numbers then HCF (a,b) is

A

`xy`

B

`xy^(2)`

C

`x^(3)y^(2)`

D

`x^(2)y^(2)`

Text Solution

AI Generated Solution

The correct Answer is:
To find the HCF (Highest Common Factor) of the two positive integers \( a \) and \( b \) given as: - \( a = x^3 y^2 \) - \( b = x y^3 \) where \( x \) and \( y \) are prime numbers, we can follow these steps: ### Step 1: Write down the prime factorization of \( a \) and \( b \) - For \( a \): \[ a = x^3 y^2 = x \cdot x \cdot x \cdot y \cdot y \] - For \( b \): \[ b = x y^3 = x \cdot y \cdot y \cdot y \] ### Step 2: Identify the common prime factors Now, we will identify the common prime factors in \( a \) and \( b \): - The prime factor \( x \) appears in both \( a \) and \( b \). - The prime factor \( y \) appears in both \( a \) and \( b \). ### Step 3: Determine the lowest power of each common prime factor - For the prime factor \( x \): - In \( a \), the power of \( x \) is \( 3 \). - In \( b \), the power of \( x \) is \( 1 \). - The minimum power is \( \min(3, 1) = 1 \). - For the prime factor \( y \): - In \( a \), the power of \( y \) is \( 2 \). - In \( b \), the power of \( y \) is \( 3 \). - The minimum power is \( \min(2, 3) = 2 \). ### Step 4: Write the HCF using the common prime factors and their lowest powers Now, we can write the HCF as: \[ \text{HCF}(a, b) = x^{\min(3, 1)} \cdot y^{\min(2, 3)} = x^1 \cdot y^2 = xy^2 \] ### Final Answer Thus, the HCF of \( a \) and \( b \) is: \[ \text{HCF}(a, b) = xy^2 \] ---
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