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An electric kettle of 2 kW works for 2 H...

An electric kettle of 2 kW works for 2 H daily. Calculate the (i) energy consumed in SI and commercial unit, (ii) cost of running it in the month of June at the rate of Rs. 3 per unit.

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To solve the problem step by step, we will calculate the energy consumed by the electric kettle in both SI and commercial units, and then find the cost of running it for the month of June. ### Step 1: Calculate energy consumed in SI units (Joules) 1. **Identify the power and time:** - Power of the kettle = 2 kW = 2000 W (since 1 kW = 1000 W) - Time = 2 hours = 2 × 60 minutes/hour × 60 seconds/minute = 7200 seconds ...
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