A houeshold uses the following electric appliances :
(a) Refrigerator of rating 400 W for ten hours each day.
(b) Two electric fans of rating 80 W each for twelve hours each day.
(c ) Six electric tubes of rating 18 W each for 6 hours each day.
Calculate the electricity bill of the household for the month of the june if the cost per unit of electric energy is `₹ 3.00`.

Explanation

(i) Electricity consumed by refrigerator in one day = power time = 400 W `xx` 10 h = 4000 Wh = 4 kWh
(ii)Electricity consumed by 2 electric fans in 1 day = power Time = `2xx80 Wxx12` h = 1920 Wh = 1.92 kWh
(iii) Electricity consumed by 6 electric tubes in 1 day = `6xx18 Wxx6` h = 648 Wh = 0.648 kWh
Total energy consumed in one day = 4 + 1.92 + 0.648 = 6.548 kWh
Total energy consumed in one month = `6.568xx30` = 197.04 kWh
Cost of 1 unit (kWh) = Rs.3.00
Cost of 197.04 kWh = `197.04xx3`
Electricity bill = Rs.591.12