A battery of 10 volt carries 20,000 C of charge through a resistance of 20 `Omega` . The work done in 10 seconds is

Options

A. `2xx10^2` Joule
B. `2xx10^5` Joule
C. `2xx10^4` Joule
D. `2xx10^2` Joule

Explanation

To solve the problem, we need to calculate the work done by the battery when it carries a charge through a resistance. The formula we will use is:

\[ \text{Work} = \text{Voltage} \times \text{Charge} \]

### Step-by-step Solution:

1. **Identify the Given Values:**
- Voltage (V) = 10 volts
- Charge (Q) = 20,000 coulombs
- Resistance (R) = 20 ohms (not needed for this calculation)
- Time (t) = 10 seconds (not needed for this calculation)

2. **Use the Formula for Work Done:**
The work done by the battery can be calculated using the formula:
\[ \text{Work} = \text{Voltage} \times \text{Charge} \]

3. **Substitute the Values:**
\[ \text{Work} = 10 \, \text{volts} \times 20,000 \, \text{coulombs} \]

4. **Calculate the Work Done:**
\[ \text{Work} = 10 \times 20,000 = 200,000 \, \text{joules} \]

5. **Express the Result in Scientific Notation:**
\[ \text{Work} = 2 \times 10^5 \, \text{joules} \]

### Final Answer:
The work done in 10 seconds is \( 2 \times 10^5 \) joules.