The resistance of an electric bulb drawing 1.2 A current at 6 V will be

Options

A. 0.5 ohm
B. 5 ohm
C. 0.2 ohm
D. 2 ohm

Explanation

To find the resistance of the electric bulb, we can use Ohm's Law, which states that:

\[ V = I \times R \]

Where:
- \( V \) is the voltage (in volts),
- \( I \) is the current (in amperes),
- \( R \) is the resistance (in ohms).

### Step 1: Identify the given values
From the question, we have:
- Voltage (\( V \)) = 6 V
- Current (\( I \)) = 1.2 A

### Step 2: Rearrange the formula to solve for resistance
We need to find \( R \), so we can rearrange the formula:

\[ R = \frac{V}{I} \]

### Step 3: Substitute the values into the formula
Now we can substitute the known values into the rearranged formula:

\[ R = \frac{6 \, \text{V}}{1.2 \, \text{A}} \]

### Step 4: Perform the calculation
Now, we calculate the resistance:

\[ R = \frac{6}{1.2} = 5 \, \text{ohms} \]

### Conclusion
The resistance of the electric bulb is \( 5 \, \text{ohms} \).

---