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In a right-angled triangle ABC, angleC ...

In a right-angled triangle ABC, `angleC = 90^(@)` and CD is perpendicular to AB. If AB x CD = CA x CB, then `1/(CD^(2))` is equal to:

A

`1/(AB)^(2) - 1/(CA)^(2)`

B

`1/(AB)^(2) - 1/(CB)^(2)`

C

`1/(BC^(2)) + 1/(CA)^(2)`

D

`1/(BC)^(2) - 1/(CA^(2))` if `CA gt CB`

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