x = ( sqrt ( a + b ) - sqrt (a -b ))/( s...

`x = ( sqrt ( a + b ) - sqrt (a -b ))/( sqrt (a +b ) + sqrt (a -b )),` then what is `bx ^(2) - 2ax + b ` equal to ` (b ne 0)` ?

A

0

B

1

C

ab

D

2 ab

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