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In a school 4 students A, B, C and D appeared in an English examination which is consist of 15 short and 4 long questions are asked. Each of short question carry 5 marks and each of long questions carry 10 mark and for a spelling error 0.5 mark is deducted. For not attempting a question, zero marks is awarded. In the English exam, A answered (x + 6) short questions, x long questions and did (2x + 10) spelling errors. Ratio of number of spelling errors made by A and B is 8 : 3. Total marks scored by D is 86. Ratio of short and long questions answered by B In the English exam is 5 : 1 and he scored total 102 marks. C scored 35 marks more in short questions than long questions except spelling errors and the number of spelling errors made by C is equal to the difference of the number of spelling errors made by A and B. Number of short questions answered by D is average of that answered by A and B. Percentage of number of long questions answered among all the question answered by D is `20%`. Average of the number of spelling errors made by all four students A, B, C and D is 10. Each student attempts integral number of short as well as long questions.
Sum of the total number of long questions answered by A, B and D is

Text Solution

AI Generated Solution

To solve the problem step-by-step, we need to analyze the information given about the students A, B, C, and D. ### Step 1: Define Variables Let: - \( x \) = number of long questions answered by A - \( x + 6 \) = number of short questions answered by A - \( 2x + 10 \) = number of spelling errors made by A ...
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