On which day of the week does `28^(th)` August, 2009 fall ?

Options

A. Sunday
B. Monday
C. Tuesday
D. Friday

Answer

D

Explanation

`28^(th)` August, 2009=2000 years +8 years +1st January, 2009 to `28^(th)` August 2009.
Number of odd days in 2000 years =0
[`:.` Multiple of 400 years = 0 odd days]
Number of odd days in 8 years =2 leap years and 6 ordinary years.
`=(2xx2)` odd days and `(6xx1)` odd days
`=10` odd days `=(10)/(7)=3` odd days
Also,
So, number of odd days from 1st January 2009 to `28^(th)` August, 2009 `=3+0+3+2+3+2+3+0`
`=16` odd days `=(16)/(7)=2` odd days
So, total number of odd days `=(0+3+2)` odd days
`=5` odd days
So, `5^(th)` day =Friday
Therefore, `28^(th)` August, 2009 =Friday.