Home
Class 14
REASONING
A clock, which loses uniformly is 15 min...

A clock, which loses uniformly is 15 minutes fast at 9 am on 3rd of the December and is 25 minutes less than the correct time at 3 pm on 6th of the same month. At what time it was correct ?

A

2.15 am on 3rd

B

2.15 pm on 4th

C

2.15 pm on 3rd

D

2.15 am on 4th

Text Solution

Verified by Experts

The correct Answer is:
B

According to the question,
Total time from 9 am on 3rd of the December to 3 pm on 6th of the December = 3 days 6 hours
`" "=78` hours.

Also, the clock loses in 78 hours = (15 + 25) = 40 minutes.
So, the clock loses 15 minutes in `=15/40 times 78`
`" "`= 29 hours 15 minutes.
Therefore, the clock is correct after 29 hours 15 minutes from 9 am on 3rd December = 2.15 pm on 4th December.
Promotional Banner

Topper's Solved these Questions

  • CLOCKS

    LUCENT PUBLICATION|Exercise EXERCISE|16 Videos
  • CLASSIFICATION OF WORDS : ODD MAN OUT

    LUCENT PUBLICATION|Exercise Exercise-2|18 Videos
  • CODING

    LUCENT PUBLICATION|Exercise EXERCISE -8|26 Videos

Similar Questions

Explore conceptually related problems

At watch, which gains uniformly, is 3 minutes slow at 12 noon on Sunday and is 5 minutes 36 seconds fast at 4 pm on the next Sunday. At what time it was correct ?

My watch, which gains uniformly, is 2 minutes slow at noon on Sunday, and is 4 minutes 48 seconds fast at 2 pm on the following Sunday. When was it correct?

In every 30 minutes the time of a watch increases by 3 minutes. After setting the correct time at 5 a.m. what time will the watch show after 6 hours ?

A clock is displaying correct time at 9am on Monday. If the clock loses 12 minutes in 24 hours, then the actual time when the clock indicates 8:30 pm on Wednesday of the same week is (a) 8 pm (b) 7 pm (c) 9 pm (d) 8:59 :45 pm

A clock is set right at 8 a.m. the clock uniformly loses 24 minutes in a day. What will be the right time when the clock indicates 4 pm on the next day ?

At t minutes past 2 pm, the time needed by the minutes hand of a clock to show 3pm was found to be 3 minutes less than (t^2)/4 minutes. Find t.