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What is the least common multiple of 24,...

What is the least common multiple of 24, 48 and 72?

A

A)72

B

B)144

C

C)288

D

D)216

Text Solution

AI Generated Solution

The correct Answer is:
To find the least common multiple (LCM) of the numbers 24, 48, and 72, we can follow these steps: ### Step 1: Prime Factorization First, we need to find the prime factorization of each number. - **For 24**: - 24 can be divided by 2: \( 24 \div 2 = 12 \) - 12 can be divided by 2: \( 12 \div 2 = 6 \) - 6 can be divided by 2: \( 6 \div 2 = 3 \) - 3 is a prime number. Therefore, the prime factorization of 24 is: \[ 24 = 2^3 \times 3^1 \] - **For 48**: - 48 can be divided by 2: \( 48 \div 2 = 24 \) - 24 can be divided by 2: \( 24 \div 2 = 12 \) - 12 can be divided by 2: \( 12 \div 2 = 6 \) - 6 can be divided by 2: \( 6 \div 2 = 3 \) - 3 is a prime number. Therefore, the prime factorization of 48 is: \[ 48 = 2^4 \times 3^1 \] - **For 72**: - 72 can be divided by 2: \( 72 \div 2 = 36 \) - 36 can be divided by 2: \( 36 \div 2 = 18 \) - 18 can be divided by 2: \( 18 \div 2 = 9 \) - 9 can be divided by 3: \( 9 \div 3 = 3 \) - 3 is a prime number. Therefore, the prime factorization of 72 is: \[ 72 = 2^3 \times 3^2 \] ### Step 2: Identify the Highest Powers Next, we identify the highest powers of each prime factor from the factorizations: - For the prime number 2: - Highest power from 24: \( 2^3 \) - Highest power from 48: \( 2^4 \) - Highest power from 72: \( 2^3 \) The highest power is \( 2^4 \). - For the prime number 3: - Highest power from 24: \( 3^1 \) - Highest power from 48: \( 3^1 \) - Highest power from 72: \( 3^2 \) The highest power is \( 3^2 \). ### Step 3: Calculate the LCM Now, we can calculate the LCM by multiplying the highest powers of all prime factors together: \[ \text{LCM} = 2^4 \times 3^2 \] Calculating this: - \( 2^4 = 16 \) - \( 3^2 = 9 \) Now, multiply these results: \[ \text{LCM} = 16 \times 9 = 144 \] ### Conclusion Thus, the least common multiple of 24, 48, and 72 is: \[ \text{LCM} = 144 \] ### Answer The correct option is **B) 144**.
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