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How many digits are there in 2^(10)xx5^(...

How many digits are there in `2^(10)xx5^(8)` ?

A

A)8

B

B)9

C

C)10

D

D)18

Text Solution

AI Generated Solution

The correct Answer is:
To find out how many digits are in the expression \(2^{10} \times 5^{8}\), we can follow these steps: ### Step 1: Rewrite the expression We start with the expression: \[ 2^{10} \times 5^{8} \] We can separate \(2^{10}\) into \(2^{8} \times 2^{2}\): \[ 2^{10} \times 5^{8} = (2^{8} \times 5^{8}) \times 2^{2} \] ### Step 2: Simplify the expression Now, we can simplify \(2^{8} \times 5^{8}\) as follows: \[ 2^{8} \times 5^{8} = (2 \times 5)^{8} = 10^{8} \] So, we rewrite the expression: \[ (10^{8}) \times 2^{2} \] ### Step 3: Calculate \(2^{2}\) Next, we calculate \(2^{2}\): \[ 2^{2} = 4 \] Thus, we can rewrite our expression as: \[ 10^{8} \times 4 \] ### Step 4: Calculate the final value Now we can calculate \(10^{8} \times 4\): \[ 10^{8} \times 4 = 4 \times 10^{8} = 400000000 \] ### Step 5: Count the digits To find the number of digits in \(400000000\), we can see that it consists of the digit '4' followed by 8 zeros. Therefore, the total number of digits is: \[ 1 \text{ (for '4')} + 8 \text{ (for the zeros)} = 9 \] ### Final Answer Thus, the total number of digits in \(2^{10} \times 5^{8}\) is: \[ \boxed{9} \] ---
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