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What is the value of 11^(2)+12^(2)+........

What is the value of `11^(2)+12^(2)+.....+20^(2)`?

A

A)3029

B

B)2485

C

C)2289

D

D)4055

Text Solution

AI Generated Solution

The correct Answer is:
To find the value of \( 11^2 + 12^2 + 13^2 + \ldots + 20^2 \), we can use the formula for the sum of squares of the first \( n \) natural numbers, which is given by: \[ \text{Sum of squares} = \frac{n(n + 1)(2n + 1)}{6} \] ### Step 1: Calculate the sum of squares from 1 to 20 We first calculate the sum of squares from \( 1^2 \) to \( 20^2 \). Here, \( n = 20 \): \[ \text{Sum from 1 to 20} = \frac{20(20 + 1)(2 \times 20 + 1)}{6} \] Calculating this step-by-step: 1. \( 20 + 1 = 21 \) 2. \( 2 \times 20 + 1 = 41 \) 3. Now substitute these values into the formula: \[ \text{Sum from 1 to 20} = \frac{20 \times 21 \times 41}{6} \] ### Step 2: Simplify the calculation Now, we can simplify: 1. Calculate \( 20 \times 21 = 420 \) 2. Now calculate \( 420 \times 41 \): \[ 420 \times 41 = 17220 \] 3. Finally, divide by 6: \[ \frac{17220}{6} = 2870 \] So, the sum of squares from \( 1^2 \) to \( 20^2 \) is \( 2870 \). ### Step 3: Calculate the sum of squares from 1 to 10 Next, we calculate the sum of squares from \( 1^2 \) to \( 10^2 \). Here, \( n = 10 \): \[ \text{Sum from 1 to 10} = \frac{10(10 + 1)(2 \times 10 + 1)}{6} \] Calculating this step-by-step: 1. \( 10 + 1 = 11 \) 2. \( 2 \times 10 + 1 = 21 \) Now substitute these values into the formula: \[ \text{Sum from 1 to 10} = \frac{10 \times 11 \times 21}{6} \] ### Step 4: Simplify the calculation Now, we can simplify: 1. Calculate \( 10 \times 11 = 110 \) 2. Now calculate \( 110 \times 21 \): \[ 110 \times 21 = 2310 \] 3. Finally, divide by 6: \[ \frac{2310}{6} = 385 \] So, the sum of squares from \( 1^2 \) to \( 10^2 \) is \( 385 \). ### Step 5: Calculate the desired sum Now, we can find the sum from \( 11^2 \) to \( 20^2 \): \[ 11^2 + 12^2 + \ldots + 20^2 = \text{Sum from 1 to 20} - \text{Sum from 1 to 10} \] Substituting the values we found: \[ 11^2 + 12^2 + \ldots + 20^2 = 2870 - 385 = 2485 \] ### Final Answer Thus, the value of \( 11^2 + 12^2 + \ldots + 20^2 \) is \( 2485 \).
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  • What is the value of sqrt(3^(4)+12^(2))

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    B
    198
    C
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