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A number is increased first by 10% and t...

A number is increased first by `10%` and then it is decreased by `10%` .What is the percentage change in the number ? (a)`11%` increase (b)No change (c)`1%` decrease (d)`11%` decrease

A

`11%` increase

B

No change

C

`1%` decrease

D

`11%` decrease

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem step by step, we will follow the changes made to the number and calculate the overall percentage change. **Step 1: Let the initial number be 100.** - This is a convenient choice because it makes percentage calculations straightforward. **Step 2: Increase the number by 10%.** - Calculation: \[ \text{Increased number} = 100 + (10\% \text{ of } 100) = 100 + 10 = 110 \] **Step 3: Decrease the new number (110) by 10%.** - Calculation: \[ \text{Decreased number} = 110 - (10\% \text{ of } 110) = 110 - 11 = 99 \] **Step 4: Calculate the overall change from the original number (100) to the final number (99).** - Change in number: \[ \text{Change} = 99 - 100 = -1 \] **Step 5: Calculate the percentage change.** - Percentage change formula: \[ \text{Percentage change} = \left(\frac{\text{Change}}{\text{Original number}}\right) \times 100 = \left(\frac{-1}{100}\right) \times 100 = -1\% \] Thus, the final answer is that there is a **1% decrease** in the number.
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