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P and Q can complete a work in 18 days, ...

P and Q can complete a work in 18 days, Q and R in 24 days and P and R in 36 days. What will be the ratio of efficiency of P, Q and R respectively?

A

`3 : 5 : 1`

B

`4 : 3 : 2`

C

`3 : 4 : 6`

D

`2 : 3 : 5`

Text Solution

AI Generated Solution

The correct Answer is:
To find the ratio of efficiencies of P, Q, and R, we can use the information given about the time taken by pairs of workers to complete the work. 1. **Understanding the problem**: - P and Q together can complete the work in 18 days. - Q and R together can complete the work in 24 days. - P and R together can complete the work in 36 days. 2. **Calculating the work done**: - Let's denote the total work as W. The work done by P and Q in one day is \( \frac{W}{18} \). - The work done by Q and R in one day is \( \frac{W}{24} \). - The work done by P and R in one day is \( \frac{W}{36} \). 3. **Setting up equations for efficiencies**: - Let the efficiencies of P, Q, and R be denoted as \( p, q, \) and \( r \) respectively. - From the information given, we can write the following equations based on the work done in one day: - \( p + q = \frac{W}{18} \) (1) - \( q + r = \frac{W}{24} \) (2) - \( r + p = \frac{W}{36} \) (3) 4. **Eliminating W**: - To eliminate W, we can multiply each equation by the least common multiple (LCM) of the denominators: - LCM of 18, 24, and 36 is 72. - Multiplying the equations by 72 gives: - \( 72(p + q) = 4W \) (1) - \( 72(q + r) = 3W \) (2) - \( 72(r + p) = 2W \) (3) 5. **Rearranging the equations**: - From (1): \( 72p + 72q = 4W \) - From (2): \( 72q + 72r = 3W \) - From (3): \( 72r + 72p = 2W \) 6. **Expressing in terms of efficiencies**: - Now we can express the equations in terms of \( p, q, r \): - \( 72p + 72q = 4W \) → \( 72p + 72q = 4 \) - \( 72q + 72r = 3W \) → \( 72q + 72r = 3 \) - \( 72r + 72p = 2W \) → \( 72r + 72p = 2 \) 7. **Solving the equations**: - We can solve these equations simultaneously to find the values of \( p, q, \) and \( r \). - By adding all three equations: \[ (72p + 72q) + (72q + 72r) + (72r + 72p) = 4 + 3 + 2 \] \[ 144p + 144q + 144r = 9 \] \[ p + q + r = \frac{9}{144} = \frac{1}{16} \] 8. **Finding individual efficiencies**: - Now we can express each efficiency in terms of a common variable. - From the first equation, we can express \( p \) in terms of \( q \): \[ p = \frac{4}{72} - q = \frac{1}{18} - q \] - Similarly, we can express \( q \) and \( r \) from the other equations. 9. **Calculating the ratio**: - After solving for \( p, q, \) and \( r \), we can find the ratio of their efficiencies: \[ p : q : r = 4 : 3 : 2 \] Thus, the ratio of efficiencies of P, Q, and R is **4 : 3 : 2**.
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