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Alloys A and B contain copper and zink i...

Alloys A and B contain copper and zink in the ratio `1 :3` and `3 :5` , respectively . In What ratio A and B be mixed to get a new alloy containing copper and zink in the ratio `1 :2` ?

A

`3 :4`

B

`2 :1`

C

`1 :2`

D

`4 :5`

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AI Generated Solution

The correct Answer is:
To solve the problem of mixing alloys A and B to achieve a new alloy with a copper to zinc ratio of 1:2, we will follow these steps: ### Step 1: Define the composition of alloys A and B Alloy A has copper and zinc in the ratio of 1:3. This means: - Copper in Alloy A = 1 part - Zinc in Alloy A = 3 parts Alloy B has copper and zinc in the ratio of 3:5. This means: - Copper in Alloy B = 3 parts - Zinc in Alloy B = 5 parts ### Step 2: Express the quantities in terms of a variable Let’s assume we take x parts of Alloy A and y parts of Alloy B. For Alloy A: - Copper from A = \( \frac{1}{4}x \) (since total parts = 1 + 3 = 4) - Zinc from A = \( \frac{3}{4}x \) For Alloy B: - Copper from B = \( \frac{3}{8}y \) (since total parts = 3 + 5 = 8) - Zinc from B = \( \frac{5}{8}y \) ### Step 3: Set up the equation for the new alloy We want the new alloy to have a copper to zinc ratio of 1:2. Therefore, we can set up the equation: \[ \frac{\text{Copper from A} + \text{Copper from B}}{\text{Zinc from A} + \text{Zinc from B}} = \frac{1}{2} \] Substituting the expressions we found: \[ \frac{\frac{1}{4}x + \frac{3}{8}y}{\frac{3}{4}x + \frac{5}{8}y} = \frac{1}{2} \] ### Step 4: Cross-multiply to eliminate the fraction Cross-multiplying gives us: \[ 2\left(\frac{1}{4}x + \frac{3}{8}y\right) = 1\left(\frac{3}{4}x + \frac{5}{8}y\right) \] ### Step 5: Simplify the equation Expanding both sides: \[ \frac{1}{2}x + \frac{3}{4}y = \frac{3}{4}x + \frac{5}{8}y \] Now, we can multiply through by 8 to eliminate the denominators: \[ 4x + 6y = 6x + 5y \] ### Step 6: Rearranging the equation Rearranging gives: \[ 4x - 6x + 6y - 5y = 0 \] \[ -2x + y = 0 \] \[ y = 2x \] ### Step 7: Find the ratio of A to B Now, we can express the ratio of A to B: \[ \frac{x}{y} = \frac{x}{2x} = \frac{1}{2} \] Thus, the ratio of Alloy A to Alloy B is 1:2. ### Final Answer The alloys A and B should be mixed in the ratio **1:2** to achieve the desired copper to zinc ratio of 1:2. ---
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