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In triangle ABC ,AD is the bisector of a...

In `triangle ABC` ,AD is the bisector of `angle A`,meets BC at D. If BC = a, AC = b and AB = c, then BD - DC=
त्रिभुज ABC में, AD, जो कोण A का समद्विभाजक है ,BC से D पर मिलता है| यदि BC = a, AC = b और AB =c है, तो BD - DC = ?

A

`(a(c+b))/(c-b)`

B

`(ab)/(b+c)`

C

`(a(c-b))/(c+b)`

D

`(ac)/(b+c)`

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The correct Answer is:
D
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