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If (a + b - c) : ( b + c - a) : (a + c -...

If `(a + b - c) : ( b + c - a) : (a + c - b) = 6 : 5 : 7`, then `(1)/(a) : (1)/(b) : (1)/( c)` is equal to:

A

`156 : 132 : 143`

B

`132 : 156 : 143`

C

`156 : 143 : 132`

D

`143 : 156 : 132`

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AI Generated Solution

The correct Answer is:
To solve the problem, we start with the given ratio: \[ (a + b - c) : (b + c - a) : (a + c - b) = 6 : 5 : 7 \] ### Step 1: Set up equations based on the ratio Let: \[ a + b - c = 6x \] \[ b + c - a = 5x \] \[ a + c - b = 7x \] ### Step 2: Add all three equations Now, we add these three equations together: \[ (a + b - c) + (b + c - a) + (a + c - b) = 6x + 5x + 7x \] This simplifies to: \[ (a + b - c + b + c - a + a + c - b) = 18x \] The left-hand side simplifies to: \[ a + b + c = 18x \] ### Step 3: Express \(c\) in terms of \(x\) Using the first equation: \[ a + b - c = 6x \implies c = a + b - 6x \] Substituting \(c\) into \(a + b + c = 18x\): \[ a + b + (a + b - 6x) = 18x \] \[ 2a + 2b - 6x = 18x \] \[ 2a + 2b = 24x \implies a + b = 12x \] ### Step 4: Express \(a\) and \(b\) in terms of \(x\) Now, substituting \(a + b = 12x\) into the equations: 1. From \(a + b - c = 6x\): \[ c = 12x - 6x = 6x \] 2. From \(b + c - a = 5x\): \[ b + 6x - a = 5x \implies b - a = -x \implies b = a - x \] 3. From \(a + c - b = 7x\): \[ a + 6x - (a - x) = 7x \implies 6x + x = 7x \] This is consistent. ### Step 5: Substitute to find \(a\) and \(b\) Now substituting \(b = a - x\) into \(a + b = 12x\): \[ a + (a - x) = 12x \implies 2a - x = 12x \implies 2a = 13x \implies a = \frac{13x}{2} \] \[ b = a - x = \frac{13x}{2} - x = \frac{11x}{2} \] \[ c = 6x \] ### Step 6: Find \(\frac{1}{a} : \frac{1}{b} : \frac{1}{c}\) Now we need to find: \[ \frac{1}{a} : \frac{1}{b} : \frac{1}{c} = \frac{2}{13x} : \frac{2}{11x} : \frac{1}{6x} \] ### Step 7: Simplify the ratios To simplify: \[ \frac{2}{13x} : \frac{2}{11x} : \frac{1}{6x} = \frac{2}{13} : \frac{2}{11} : \frac{1}{6} \] Multiplying through by \(78\) (the LCM of \(13\), \(11\), and \(6\)): \[ \frac{2 \cdot 6}{13} : \frac{2 \cdot 6}{11} : \frac{78}{6} = \frac{12}{13} : \frac{12}{11} : 13 \] ### Final Step: Convert to integer ratios The final ratio is: \[ \frac{12 \cdot 11 \cdot 6}{13 \cdot 11 \cdot 6} : \frac{12 \cdot 13 \cdot 6}{13 \cdot 11 \cdot 6} : \frac{12 \cdot 13 \cdot 11}{13 \cdot 11 \cdot 6} \] This gives us: \[ \frac{156}{132} : \frac{132}{156} : \frac{143}{156} \] Thus, the answer is: \[ \frac{156}{132} : \frac{132}{156} : \frac{143}{156} \] ### Final Result The answer is \(156 : 132 : 143\).
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