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A is 20% more than B, B is 25% more than...

A is `20%` more than B, B is `25%` more than C, C is `50%` less than D and D is `10%` more than E. Which of the following is true?

A

A is `17.5%` less than E

B

D is `30%` less than B

C

A is `40%` less than D

D

C is `24%` less than A

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The correct Answer is:
To solve the problem step by step, we will define the relationships between A, B, C, D, and E based on the percentages given. ### Step 1: Define the variables Let: - C = x (we will express all other variables in terms of x) ### Step 2: Express B in terms of C B is 25% more than C: \[ B = C + 0.25C = 1.25C = 1.25x \] ### Step 3: Express A in terms of B A is 20% more than B: \[ A = B + 0.20B = 1.20B = 1.20(1.25x) = 1.50x \] ### Step 4: Express D in terms of C C is 50% less than D: \[ C = D - 0.50D = 0.50D \] Thus, \[ D = \frac{C}{0.50} = 2C = 2x \] ### Step 5: Express E in terms of D D is 10% more than E: \[ D = E + 0.10E = 1.10E \] Thus, \[ E = \frac{D}{1.10} = \frac{2x}{1.10} = \frac{20x}{11} \] ### Step 6: Combine the relationships Now we have: - A = 1.50x - B = 1.25x - C = x - D = 2x - E = \(\frac{20x}{11}\) ### Step 7: Find the ratio A to E To find the ratio of A to E: \[ A : E = 1.50x : \frac{20x}{11} \] This simplifies to: \[ A : E = 1.50 : \frac{20}{11} \] To simplify further, multiply both sides by 11: \[ A : E = 1.50 \times 11 : 20 = 16.5 : 20 \] Now, we can convert this to a simpler ratio: \[ A : E = 33 : 40 \] ### Step 8: Calculate the percentage difference To find how much A is less than E: \[ \text{Difference} = E - A = \frac{20x}{11} - 1.50x \] Convert 1.50x to a fraction with a denominator of 11: \[ 1.50x = \frac{16.5x}{11} \] Now, substituting back: \[ \text{Difference} = \frac{20x}{11} - \frac{16.5x}{11} = \frac{3.5x}{11} \] Now, to find the percentage difference: \[ \text{Percentage} = \left(\frac{\text{Difference}}{E}\right) \times 100 = \left(\frac{\frac{3.5x}{11}}{\frac{20x}{11}}\right) \times 100 = \left(\frac{3.5}{20}\right) \times 100 = 17.5\% \] ### Conclusion Thus, A is 17.5% less than E.
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