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Assertion (A) : (A + B) ^(2) ne A^(2) + ...

Assertion (A) : `(A + B) ^(2) ne A^(2) + 2AB + B^(2)`
Reason (R) : Generally ` AB ne BA `

A

Both A and R are true and R is the correct explanation of A

B

Both A and R are true but R is NOT the correct explanation of A

C

A is true but R is false

D

A is false and R is true

Text Solution

AI Generated Solution

The correct Answer is:
To solve the given assertion and reason, we need to analyze the statement step by step. **Assertion (A):** \((A + B)^2 \neq A^2 + 2AB + B^2\) **Reason (R):** Generally, \(AB \neq BA\) ### Step-by-step Solution: 1. **Expand the Left Side:** We start with the left-hand side of the assertion: \[ (A + B)^2 = (A + B)(A + B) \] Using the distributive property (also known as the FOIL method for binomials), we get: \[ (A + B)(A + B) = A^2 + AB + BA + B^2 \] 2. **Combine Like Terms:** Now, we can combine the terms: \[ A^2 + B^2 + AB + BA \] Notice that \(AB\) and \(BA\) are separate terms. 3. **Recognize the Non-commutative Property:** In matrix multiplication, \(AB\) is not necessarily equal to \(BA\). Therefore, we cannot combine \(AB\) and \(BA\) into \(2AB\) because they are distinct products: \[ A^2 + B^2 + AB + BA \neq A^2 + 2AB + B^2 \] 4. **Conclusion for Assertion:** Since we have shown that: \[ (A + B)^2 = A^2 + B^2 + AB + BA \] and this is not equal to \(A^2 + 2AB + B^2\), the assertion is true: \[ (A + B)^2 \neq A^2 + 2AB + B^2 \] 5. **Conclusion for Reason:** The reason states that \(AB \neq BA\) is generally true for matrices. This is a fundamental property of matrix multiplication. 6. **Final Conclusion:** Both the assertion and the reason are correct. Therefore, the correct option would be the one that states both the assertion and reason are true.
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