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Two batteries of emf epsilon(1) and epsi...

Two batteries of emf `epsilon_(1)` and `epsilon_(2) (epsilon_(2)gtepsilon_(1)` and internal resistances `r_(1)` and `r_(2)` respectively are connected in parallel as shown in Fig. 2 (EP).1.

A

The equivalent emf `epsilon_(eq)` of the two cells is between `epsilon_(1)` and `epsilon_(2), i.e. epsilon_(1) lt epsilon_(2)`.

B

The equivalent emf `epsilon_(eq)` is smaller than `epsilon_(1)`.

C

The `epsilon_(eq)` is given by `epsilon_(eq)=epsilon_(1) + epsilon_(2)` always.

D

`epsilon_("eq")` is independent of internal resistances `r_(1) and r_(2)`

Text Solution

Verified by Experts

The correct Answer is:
A
As we know that the equivalent emf in parallel combination of cells is :
`epsilon_(eq) = ((epsilon_(1) r_(2) +epsilon_(2)r_(1)))/((r_(1)+r_(2)))`
so, it is clear that part .c. and .d. are incorrect by formula. According to this formula only option (A), is correct.
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