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An EM wave radiation outwards from a dip...

An EM wave radiation outwards from a dipole antenna, with `E_0` as the amplitude of its electric field vector. The electric field `E_0` which transports signification energy from the source falls off as

A

`(1)/(r^(3))`

B

`(1)/(r^(2))`

C

`(1)/(r)`

D

remains constant

Text Solution

Verified by Experts

The correct Answer is:
C
A diode antenna radiates the electromagnetic waves outwards. The amplitude of electric field vector `(E_(0))` which fransports significant energy from the source falls inversely as the distance (r) from the antenna. As we know that electromagnetic waves are radiated from dipole antenna and radiated energy, so `E prop (1)/(r)`.
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